Question #e47bf

2 Answers
Oct 27, 2017

The first number is -14 and the second number is -8.

Explanation:

Let a be the first number.
Let b be the second number.

We have two equations from the question:
#a = b - 6# (1st number = 6 less than 2nd number)

#2b = 4a + 40# (twice the 2nd number is 40 more than 4 times the 1st)
In this equation here, let's make b by itself:
#b = 2a + 20# (divided 2 on both sides of the equation)

So our 2 equations are:
#a = b - 6# and
#b = 2a + 20#

Let's plug in the value of b into the 1st equation so that we can solve for a:
#a = (2a + 20) - 6#
#a = 2a + 14#
#-a = 14#
#a = -14#

Now that we have the value of a, we can find b.
#-14 = b - 6#
#-8 = b#
#b = -8#

Now, we should check our answer by plugging the numbers into the other equation and seeing if both sides of the equation are equal:
#-8 = 2(-14) + 20#
#-8 = -28 + 20#
#-8 = -8# :)

The first number is -14 and the second number is -8.

Oct 27, 2017

The two numbers are #-8 and -14#

Explanation:

Given that: One number is 6 less than a second number.

Let the second number be #x#.

So, the first number will be #x-6#.

Twice the second number is 40 more than 4 times the first.
Means:

#2xxx=40+4xx(x-6)#

#=> 2x = 40 + 4x -24#

Take the terms with variable #x# on left hand side of equation and remaining on right hand side:

#=>2x - 4x = 40- 24#

#=> -2x = 16#

# x = -8#
So the second number is #-8#
and
the first number is #x-6 = -8-6=-14#

#therefore# The two numbers are #-8 and -14#