How do you graph and solve #2x-abs[x+4]> 8#?

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Answer 1 · 2017-10-27T22:37:18

#x > 12#

#2x-abs(x+4)=8+epsilon^2# with #epsilon ne 0# or

#2x-8-epsilon^2= abs(x+4)# or

#(2x-8-epsilon^2)^2-(x+4)^2=0# or

#(-epsilon^2 - 12 + x) (-epsilon^2 - 4 + 3 x) = 0# or

#{(-epsilon^2 - 12 + x=0),(-epsilon^2 - 4 + 3 x=0):}#

or

#{(x > 12),(x > 4/3):}#

and the solution is #x > 12#