Question

Question #a0de1

Answer 1

See the answer below...

Explanation:

The wheel with a diameter of `30`inch overcomes a distance of (`pixx`diameter`xx`n revolutions)=`pixx30xx240=7200pi` inch

In this case the second wheel will also overcome a same distance i.e, `7200pi` inch.
The diameter of the second wheel is `20` inch hence its circumference will be `20xxpi=20pi` inch.

So the second wheel will have to complete `(7200pi)/(20pi)=360` revolutions...

Hope it helps...
Thank you...

Answer 2

The small wheel will revolve 360 times in the same distance.

Explanation:

These two wheels may be on one side of a wagon with the front steering wheels smaller than the load carrying wheels at the back.

Then in the same distance:

The `30i` wheel turns `240` times for a distance of `30i(240)`.
The `20i` wheel turns `T` times for a distance of #20i(T) .

And: `(30i)(240)=20iT`

`720canceli=20canceliT`

`360=T`