How do you solve $(6 x + 5) (x - 3) = - 2 x (7 x + 5) + x - 12$ $(6x + 5)( x - 3) = - 2x ( 7x + 5) + x - 12$ ?

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How do you solve $(6 x + 5) (x - 3) = - 2 x (7 x + 5) + x - 12$ $(6x + 5)( x - 3) = - 2x ( 7x + 5) + x - 12$ ?

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Answer 1 · 2017-10-29T07:03:32

the answers are $x = \frac{1}{2}, \frac{- 3}{10}$ $x=1/2,(-3)/10$

Explanation:

the given question is $(6 x + 5) (x - 3) = - 2 x (7 x + 5) + x - 12$ $(6x+5)(x-3)=-2x(7x+5)+x-12$
$\Rightarrow 6 x^{2} - 18 x + 5 x - 15 = - 14 x^{2} - 10 x + x - 12 \Rightarrow 6 x^{2} - 13 x - 15 = - 14 x^{2} - 9 x - 12$ $rArr6x^2-18x+5x-15=-14x^2-10x+x-12 rArr6x^2-13x-15=-14x^2-9x-12$
$\Rightarrow 20 x^{2} - 4 x - 3 = 0$ $rArr20x^2-4x-3=0$
$\Rightarrow 20 x^{2} - 10 x + 6 x - 3 = 0$ $rArr20x^2-10x+6x-3=0$
$\Rightarrow (10 x + 3) (2 x - 1) = 0$ $rArr(10x+3)(2x-1)=0$
$\Rightarrow x = \frac{1}{2}, \frac{- 3}{10}$ $rArrx=1/2,(-3)/10$

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How do you solve $(6 x + 5) (x - 3) = - 2 x (7 x + 5) + x - 12$ $(6x + 5)( x - 3) = - 2x ( 7x + 5) + x - 12$ ?

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Explanation:

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How do you solve (6x+5)(x−3)=−2x(7x+5)+x−12(6x + 5)( x - 3) = - 2x ( 7x + 5) + x - 12?

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Explanation:

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How do you solve $(6 x + 5) (x - 3) = - 2 x (7 x + 5) + x - 12$ $(6x + 5)( x - 3) = - 2x ( 7x + 5) + x - 12$ ?