Question

Question #51f38

Answer 1

There are approximately `2.38` moles of sodium bicarbonate in `"200 g"`.

Explanation:

We must first find the molar mass of sodium bicarbonate, `"NaHCO"_3`.

We do this as follows:

1) Find the molar mass of each element in the compound.

• `"Na = 22.99 g/mol"`
• `"H = 1.008 g/mol"`
• `"C = 12.01 g/mol"`
• `"O = 16.00 g/mol"`

2) Add up the molar masses to find the molar mass of the compound.

`1(22.99) + 1(1.008) + 1(12.01) + 3(16.00) = "84.008 g/mol"`

This means that each mole of sodium bicarbonate weighs about `84.008` grams.

3) Divide the number of grams by the molar mass to find moles.

`"200 g"/"84.008 g/mol" = "2.38 moles"`

Note: Keep in mind that you have one significant figure for the mass of sodium bicarbonate!