Question #51f38

1 Answer
Oct 29, 2017

There are approximately #2.38# moles of sodium bicarbonate in #"200 g"#.

Explanation:

We must first find the molar mass of sodium bicarbonate, #"NaHCO"_3#.

We do this as follows:

1) Find the molar mass of each element in the compound.

  • #"Na = 22.99 g/mol"#
  • #"H = 1.008 g/mol"#
  • #"C = 12.01 g/mol"#
  • #"O = 16.00 g/mol"#

2) Add up the molar masses to find the molar mass of the compound.

#1(22.99) + 1(1.008) + 1(12.01) + 3(16.00) = "84.008 g/mol"#

This means that each mole of sodium bicarbonate weighs about #84.008# grams.

3) Divide the number of grams by the molar mass to find moles.

#"200 g"/"84.008 g/mol" = "2.38 moles"#

Note: Keep in mind that you have one significant figure for the mass of sodium bicarbonate!