How do you solve #-58= x + 4x + 2#?

1 Answer
Pallu
Oct 30, 2017

#x=- 12#

Explanation:

#-58= x + 4x + 2#

Keep the terms with variable #x# on left hand side of the equation and bring all other terms on right hand side by applying rule of transposition:

#-x -4x =2+58#

# -5x= 60#

# x= 60/-5#

#x=- 12#

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