How do you simplify #(\frac { 6r ^ { 6} } { 9r ^ { 2} } ) ^ { 2}#?

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Answer 1 · 2017-10-30T02:57:07

#=>(4r^8)/9 = 0.4444 r^8#

#(\frac { 6r ^ { 6} } { 9r ^ { 2} } ) ^ { 2}#

#=>(\frac { cancel3xx2xxr ^ { 6} } { cancel3xx3xxr ^ { 2} } ) ^ { 2}#

#=>(2/3xx\frac { r ^ { 6} } { r ^ { 2} } ) ^ { 2}#

#=>(2/3xx\frac { r ^ { 6-2} } { 1 }) ^ { 2}#

#=>(2/3xx\frac { r ^ { 4} } { 1 }) ^ { 2} = ((2r^4)/3)^2#

Rule of indices: #(a^m)^n = a^(mn)#

#=>(2^2/3^2xx\frac {( r ^ { 4})^2 } { 1 ^2}) #

#=>(4/9xx r ^ { 8} )#

#=> (4r^8)/9 = 0.4444 r^8#