Question

How do you solve `3+ 7x = 73`?

Answer 1

`x=10`

Explanation:

`"isolate the term 7x by subtracting 3 from both sides"`

`cancel(3)cancel(-3)+7x=73-3`

`rArr7x=70`

`"divide both sides by "7`

`(cancel(7) x)/cancel(7)=70/7`

`rArrx=10`

`color(blue)"As a check"`

`3+(7xx10)=3+70=73larrcolor(blue)"True"`

`rArrx=10" is the solution"`

Answer 2

`x` = 10

Explanation:

So, what you have to do firstly is subtract the `3` from the equation so you get:
`7x = 70`

Then, you have to remember that `7x = 7 times x = 70`
So `70/7 = 10`