How do you solve #16k + 2k \geq 28#?

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Answer 1 · 2017-10-31T21:48:00

See a solution process below:

First, combine like terms on the left side of the inequality:

#(16 + 2)k >= 28#

#18k >= 28#

Next, divide each side of the inequality by #color(red)(18)# to solve for #k# while keeping the inequality balanced:

#(18k)/color(red)(18) >= 28/color(red)(18)#

#(color(red)(cancel(color(black)(18)))k)/cancel(color(red)(18)) >= 28/color(red)(18)#

#k >= 28/color(red)(18)#

Now, we can reduce the fraction on the right side of the inequality:

#k >= (2 xx 14)/color(red)(2 xx 9)#

#k >= (color(red)(cancel(color(black)(2))) xx 14)/color(red)(color(black)(cancel(color(red)(2))) xx 9)#

#k >= 14/9#