How do you evaluate #(2x + 7) ( 3x + 3)#?

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Answer 1 · 2017-10-31T21:50:07

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2x) + color(red)(7))(color(blue)(3x) + color(blue)(3))# becomes:

#(color(red)(2x) xx color(blue)(3x)) + (color(red)(2x) xx color(blue)(3)) + (color(red)(7) xx color(blue)(3x)) + (color(red)(7) xx color(blue)(3))#

#6x^2 + 6x + 21x + 21#

We can now combine like terms:

#6x^2 + (6 + 21)x + 21#

#6x^2 + 27x + 21#