How do you solve this system of equation: #6x - 10y = 2; - 9x - 2y = 16#?

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Answer 1 · 2017-11-01T15:41:30

#x=-26/17# and #y=-19/17#

#(-5)*(-9x-2y)+6x-10y=2+16*(-5)#

#51x=-78#

#x=-26/17#

Hence #6*(-26/17)-10y=2# or #-10y=-190/17#

So, #y=-19/17#

Answer 2 · 2017-11-01T15:48:16

#y=-19/17# and #x=-26/17#

#6x-10y=2#
#-9x-2y=16#

from first equation #x=(10y+2)/6#
sub into the second
#-9((10y+2)/6)-2y=16#
#-102y=114#
#y=-19/17#

sub y into equation 1

#6x-10(-19/17)=2#
#x=(2+10(-19/17))/6#
Therefore, #x=-26/17#