Question

How do you solve `25< 2x + 3x + 5`?

Answer 1

`x > 4`

Explanation:

To solve this inequality, you treat it as a regular equation.

`25 < 2x + 3x + 5`
`25 < 5x + 5`
`20 < 5x`
`4 < x`

So the answer would be any value greater than `4`, or `x>4`.

Answer 2

`x>4`

Explanation:

Except in the case where you're multiplying or dividing both sides of an inequality by a negative number, you'd approach solving an inequality like you would any other algebraic equation.

`25<2x+3x+5`
`25<5x+5` (combine like terms)
`20<5x` (subtract 5 from both sides)
`4< x` (divide both sides by 5 to isolate `x`)

`x>4`