How do you solve #\root[ 3] { 2x - 6} - 9= - 11#?

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Answer 1 · 2017-11-02T03:25:34

#therefore x = -1#

#\root[ 3] { 2x - 6} - 9= - 11#

#=> \root[ 3] { 2x - 6} = - 11+ 9#

#=> \root[ 3] { 2x - 6} = - 2#

Cube both sides:

# => { 2x - 6} = (- 2)^3#

#=> 2x - 6 = -8 #

#=> 2x = -8+6#

#=> 2x = -2#

#=> x= -2/2 = -1#

#therefore x = -1#