Question #ae181

1 Answer
Nov 2, 2017

If a is #9/b# you can find it easily by quadratic equation method.

Explanation:

Your second equation #atimesb=9# can be rewritten as #a=9/b#. Put this into the first equation:

#7times(9/b)-5timesb=6#

#63/b - 5b =6#

Multiply all terms by b.

#63 - 5timesb^2 - 6timesb = 0#

#-5b^2 -6b + 63=0# solve this equation

#Delta=36 - 4times(-5)times(63)#

#Delta = 1296#

#(Delta)^0.5 = 36#

Solution for b is #=[-(-6)-36] /(2times-5)#

#b=30/(-10) = -3#

Therefore if b is -3 a is also -3 (since #a=9/b = 9/-3 = -3#). This is the first solution (a=b=-3).

The value of #343times(a^3) - 125times(b^3) = 343times(-3^3) - 125times(-3^3) = -5886#

There is another solution

#b=[-(-6) + 36] /(2times-5)#

#b=42/-10 = -4.2#

#atimes-4.2=9#

#a=-2.1428#

This is the second solution. (a=-2.1428 and b=-4.2).

In this case, your answer is #343times(-2.1428^3) - 125times(-4.2^3) = 5886#