Question

A 50 kg skater pushed by a friend accelerates at 5 m/s. How much force did the friend apply?

Answer 1

`F= 250 N`

Explanation:

`F= ma` -----Newton's second law.

We know : `m =50kg and a= 5 m/s^2`

`therefore F= 50kg xx 5 m/s^2 = 250 N`

`F= 250 N`

Answer 2

`250` `N`

Explanation:

To solve this, we use Newton's second law of motion

`color(blue)("Force"="Mass"xx"Acceleration"` `(F=ma)`

We know that

`color(brown)("Mass"=50` `color(brown)(kg`

`color(brown)("Acceleration"=5` `color(brown)(m/s^2`

So,

`rarr50xx5`

`color(green)(rArr250` `color(green)(N`

So the skater pushed his friend with a force of `250` `N`

Hope this helps!!! ☺§☻