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Answer 1 · 2017-11-05T04:27:32

#= 390.8828 g H_2SO_4#

#2.4*10^24 mo H_2SO_4 ((1 mol H_2SO_4)/(6.022*10^23 mo H_2SO_4)) ((98.079 g H_2SO_4)/(1 mol H_2SO_4))#
#= 390.8828 g H_2SO_4#

*mo is molecules

Answer 2 · 2017-11-05T04:33:37

390.88 g of #H_2SO_4#

To solve this question we need to know the mole concept. As we know that,

1 mole = #6.022 X 10^23 "molecules"#

And we also know that the molar mass of #H_2SO_4# is 98.079 g/mol which means:

1 mole of #H_2SO_4# = 98.079 g

By using the above two relations, we get:

#6.022 X 10^23 "molecules"# of #H_2SO_4# = 98.079 g of #H_2SO_4#

or, #1 "molecules"# of #H_2SO_4# = #frac(98.079 )(6.022 X 10^23)# g of #H_2SO_4#

or , #2.4X10^24 "molecules"# of #H_2SO_4# = #frac(98.079)(6.022 X 10^23) X 2.4X10^24# g of #H_2SO_4# = 390.88 g of #H_2SO_4#

Therefore, #2.4X10^24 "molecules"# of #H_2SO_4# contain 390.88 grams of #H_2SO_4#.