Question

How many atoms are of each element are there in 9.8 g of sulphuric acid, G2SO4 ? ( atomic mass, H=1 , S=32 , O=16)

Answer 1

`1.2004*10^23` atoms / mol H
`6.022*10^22` atoms / mol S
`2.4088*10^23` atoms / mol O*

Explanation:

The molar mass of `H_2SO_4` is 98 g/mol.

For H:
`9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((2 mol H)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol H))`
`=1.2004*10^23` atoms / mol H

For S:
`9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((1 mol S)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol S))`
`=6.022*10^22` atoms / mol S

For O:
`9.8 g H_2SO_4 ((1 mol H_2SO_4)/(98 g H_2SO_4))((4 mol O)/(1 mol H_2SO_4))((6.022*10^23 atms) / (1 mol O))`
`=2.4088*10^23` atoms / mol O