Question

If `f(x)= 1/x` and `g(x) = 2e^x -4`, how do you differentiate `f(g(x))` using the chain rule?

Answer 1

`-(2e^x-4)(2e^x)`

Explanation:

`f(g(x))`
`= f(2e^x-4)`
`=1 / (2e^x-4)`

This can be rewritten as:
`(2e^x-4)^-1`

Differentiating with respect to x,
`-(2e^x-4)(2e^x)`