How do you solve #2/10=4/(a-3)#?

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Answer 1 · 2017-11-05T12:21:33

#a=23#

Multiplying both sides by #a-3#,
#2/10 (a-3) =4#

Distributing #2/10#,
#2/10 a - 6/10 = 4#
#2/10 a = 4 + 6/10#
#2/10 a = 23/5#

Dividing both sides by #2/10#,
#a=23#

Answer 2 · 2017-11-05T12:22:42

23

#2/10#=#4/(a-3)#

Multiply both sides by 10 to eliminate the fraction on the left portion

#2#=#40/(a-3)#

Then Multiple both sides by a-3 to eliminate the fraction on the right portion

#2(a-3)#=40

Distribute 2

2a-6=40

Transpose -6 to the right side

2a=40+6

2a=46

a=23