Question #433bf

1 Answer
Nov 5, 2017

38

Explanation:

Let
#x# = ones digit
#y# = tens digit

the original number = #10y + x#
the new number = #10x + y#

We also know that:
#x + y = 11#
Rearranging,
#x = 11 - y#

The statement: "the new number is 45 more than the original number" can be mathematically written as:
#10x+y = 10y + x + 45#

Writing #x# in terms of #y#,
#10(11-y)+y=10y+(11-y)+45#
#110-10y+y=10y+11-y+45#
#-10y+y-10y+y=-110+11+45#
#-18y=-54#
#y=3#

#x = 11 - y#
#x=11-3#
#x=8#

Therefore, the original number is 38