Question

How fast will an object with a mass of `8 kg` accelerate if a force of `63 N` is constantly applied to it?

Answer 1

`7.875ms^(-2)`

Explanation:

Using Newton's second Law

`F=ma`

`F=63N`the force applied

`m=8kg`the mass

`a=`acceleration

in this case

63=8a#

`:.a=63/8=7.875ms^(-2)`

Answer 2

With my chosen interpretation of the question, the acceleration is `7.9 m/s^2`.

Explanation:

If the net force on this object is 63 N, it is a simple application of `F_"net"=m*a`. But, is that 63 N one of 2 or more forces on this object?

It could be that the direction of this force is directly up and that the 8 kg object is in on Earth where `g=-9.8 m/s^2`. In that situation, we would find that the object is heavier than 63 N and it would therefore accelerate downwards more slowly than in free-fall.

But I will choose the simplest interpretation of your question: the 63 N force is applied horizontally and there is no friction.

`F_"net"=m*a`.

`63 N = 8 kg*a`

`a = (63 N)/(8 kg) = 7.9 N/(kg) = 7.9 m/s^2`

I hope this helps,
Steve