Question #1d78e
1 Answer
Nov 7, 2017
See the answer below...
Explanation:
Let's have a picture....
From the picture, you can say that...
#sin(A+B)=bar(PQ)/bar(OP) =(bar(PT)+bar(TQ))/bar(OP)=bar(PT)/bar(OP)+bar(TQ)/bar(OP)=bar(PT)/bar(OP)+bar(RS)/bar(OP)[as : bar(TQ)=bar(RS)]=(bar(PT)/bar(PR))cdot(bar(PR)/bar(OP))+(bar(RS)/bar(OR))cdot(bar(OR)/bar(OP))=cosAsinB+sinAcosB[as angleTPR=A]=sinAcosB+cosAsinB# PROVED
Hope it helps...
Thank you....
