Given the equation #x/y+5x=6+1/y#, where x can be any real number except 1 or 6/5. If y is solved in terms of x, the result is y=?

1 Answer
Nov 8, 2017

#y=(x-1)/(6-5x)#

Explanation:

You can rearrange the equation as:

#x/y-1/y=6-5x#

Factoring out #1/y# in the left hand side,
#1/y(x-1)=6-5x#

Dividing both sides by #(x-1)#,
#1/y=(6-5x)/(x-1)#

Taking the reciprocal of both sides,
#y=(x-1)/(6-5x)#