A combined circuit has two resistors in parallel (10.0 ohms and 14.0 ohms) and another in series (5.0 ohms). If the power source is 9.0 volts, what is the current?

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Answer 1 · 2017-11-08T04:41:51

#I = 0.833A#

First calculate the equivalent resistance for the parallel combination:

#1/R_(eq) = 1/ 10 + 1/14#

#=> R_(eq) = (10xx 14)/ (10+14)#

#=> R_(eq) = 140/ 24 = 5.833 ohms#

Now the total equivalent resistance will be sum of this and the one in series:

# R_(tot) = R_(eq) + 5 ohms#

# R_(tot) = 5.833 + 5 ohms = 10.833 ohms#

Given Voltage = #V = 9 V#

According to Ohms law,

#therefore I = V/R = 9/ 10.833 = 0.830# ampere