Question

What is the moment of inertia of a pendulum with a mass of `9 kg` that is `14m` from the pivot?

Answer 1

`"1764 kgm"^2`

Explanation:

`"Moment of inertia of simple pendulum = mr"^2 = "9 kg × (14 m)"^2 "= 1764 kg m"^2`