Question

How do you simplify `(\frac { 2n^0 } { m ^ { - 4} n ^ { - 2} \times n} ) ^ { 2}`?

Answer 1

`4m^4n^2`

Explanation:

`((2n^0)/(m^-4 n^-2 n))^2`

`= ((2)/(m^-4 n^(-2+1)))^2` as `n^0 = 1`

`= (2 m^4 n)^2` as `1/ m^-4 = m^4` & `1/m^-1 = n`

`= 4m^8n^2`