How do you simplify #\frac { 8u v } { 8u v - 24v }#?
1 Answer
Nov 9, 2017
Explanation:
#"factorise the denominator"#
#8uv-24v=8v(u-3)#
#rArr(8uv)/(8uv-24v)#
#=(8uv)/(8v(u-3)#
#color(blue)"cancel common factors"#
#=(cancel(8)ucancel(v))/(cancel(8v)(u-3))#
#=u/(u-3)to(u!=3)#
