How do you solve $(x - 4) \frac{2}{3} = 25$ $(x - 4) \frac { 2} { 3} = 25$ ?

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Answer 1 · 2017-11-10T04:04:24

$x = \frac{83}{2} = 41 \frac{1}{2} = 41.5$ $x=83/2=41 1/2=41.5$

Start by simplifying the problem. Get rid of the fraction by multiplying both sides by $3$ $3$ .

$(x - 4) \frac{2}{3} \times 3 = 25 \times 3$ $(x-4)2/3color(red)(xx3)=25color(red)(xx3)$

$(x - 4) 2 = 75$ $(x-4)2=75$

Distribute the $2$ $2$ into the binomial on the left

$2 x - 8 = 75$ $2x-8=75$

Add $8$ $8$ to both sides

$2 x - 8 + 8 = 75 + 8$ $2x-8color(red)(+8)=75color(red)(+8)$

$2 x = 83$ $2x=83$

Finally, divide both sides by $2$ $2$

$x = \frac{83}{2} = 41 \frac{1}{2} = 41.5$ $x=83/2=41 1/2=41.5$

How do you solve (x−4)23=25(x - 4) \frac { 2} { 3} = 25?