How do you solve #(x+4)/-7 = -3#?
2 Answers
Nov 10, 2017
Explanation:
#"multiply both sides of the equation by "-7#
#cancel(-7)^1xx(x+4)/cancel(-7)^1=-7xx-3#
#rArrx+4=21#
#"subtract 4 from both sides"#
#xcancel(+4)cancel(-4)=21-4#
#rArrx=17" is the solution"#
Nov 10, 2017
Multiply both sides by
Minus into minus = plus
Subtract both sides by 4