Question

How do you find the sum of `Sigma 2i^2` where i is [0,5]?

Answer 1

`sum_(i=0)^5 2i^2 = 110`

Explanation:

We seek:

`sum_(i=0)^5 2i^2 = 2 .0^2 + 2 .1^2 + 2 .2^2 + 2 .3^2 + 2 .4^2 + 2 .5^2`
`\ \ \ \ \ \ \ \ \ \ \ = 2 (0^2 + 1^2 + 2^2 + 3^2 + 4^2 + 5^2 )`
`\ \ \ \ \ \ \ \ \ \ \ = 2 (0 + 1 + 4+ 9 + 16 + 25 )`
`\ \ \ \ \ \ \ \ \ \ \ = 2 (55 )`
`\ \ \ \ \ \ \ \ \ \ \ = 110`