How do you find the horizontal asymptote of #f( x ) = \frac { 2} { x ^ { 2} - 8x } + 1#?

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Answer 1 · 2017-11-10T20:14:12

See below.

Vertical asymptotes occur where the function is undefined: So we are looking at the denominator being zero:

#x^2-8x=0#

#x(x-8)=0=>x=8 or x=0#

So vertical asymptote are the vertical lines:

#x=8# and #x=0# ( x = 0 is just the x axis )

Graph:

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