How do you solve #6( 1- 7x ) \geq - 8x + 40#?

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Answer 1 · 2017-11-13T02:59:30

Distribute, then isolate variables. see below.

#6(1-7x) >= -8x + 40#

distribute the 6 to the parentheses.

#6-42x >= -8x + 40#

add #42# to both sides to get variable on one side.

#6 >= 34x + 40#

subtract 40 from both sides

#-34 >= 34x#

now we divide both sides by a form of one.

#-34/34 >= (34x)/34#

#-1 >= x# or #x<=-1#