Question

How do you solve `\frac { n + 4} { 2} - 3= 13`?

Answer 1

`n=28`

Explanation:

`(n+4)/2-3=13`

(1) add 3 to both sides

`(n+4)/2cancel(-3+3)=13+3`

`(n+4)/2=16`

(2) multiply both sides by 2

`n+4=32`

(3) subtract 4 from both sides

`n+4-4=32-4`

`n=28`

Answer 2

Transfer -3 or add 3 to both sides
`(n+4)/2cancel(-3)cancel(+3)=13+3`
You get
`(n+4)/2=16`
Multiply both sides by 2
`(n+4)/cancel2 xxcancel2=16xx2`
You get
`n+4=32`
Transfer 4 or subtract both sides by 4
`n cancel(+4)cancel(-4)=32-4`
You get
`n=28`
CHECK
`(28+4)/2-3=13`
Solve
`32/2-3=13`
Solve
`(cancel32^16)/(cancel2^1) -3 =13`
You get
`16-3=13`
Solve
`13=13`
Hence, proved