Question #c2af6

1 Answer
Nov 13, 2017

#35x^6#

Explanation:

#color(blue)((49x^6)^(1/2)xx(125x^9)^(1/3)#

To solve this we use three rules

#o. color(brown)((xy)^z=z^zy^z#

#o. color(brown)((x^y)^z=x^(yz)#

#o. color(brown)(x^yxxx^z=x^(y+z)#

So, lets find the solution

#rarr(49x^6)^(1/2)xx(125x^9)^(1/3)#

Use #color(brown)((xy)^z=z^zy^z#

#rarr(49)^(1/2)xx(x^6)^(1/2)xx(125)^(1/3)xx(x^9)^(1/3)#

#rarr(7xx7)^(1/2)xx(x^6)^(1/2)xx(5xx5xx5)^(1/3)xx(x^9)^(1/3)#

#rarr(7^2)^(1/2)xx(x^6)^(1/2)xx(5^3)^(1/3)xx(x^9)^(1/3)#

Use #color(brown)((x^y)^z=x^(yz)#

#rarr(7)^((2)(1/2))xx(x)^((6)(1/2))xx(5)^((3)(1/3))xx(x)^((9)(1/3))#

#rarr7xxx^3xx5xxx^3#

Use #color(brown)(x^yxxx^z=x^(y+z)#

#color(green)(rArr35x^6#

Hope this helps!!! ☺☻