How do you solve #4p ^ { 2} - 3p + 7= 0#?

1 Answer
Nov 14, 2017

See a solution process below:

Explanation:

We can use the quadratic equation to solve this problem:

The quadratic formula states:

For #color(red)(a)x^2 + color(blue)(b)x + color(green)(c) = 0#, the values of #x# which are the solutions to the equation are given by:

#x = (-color(blue)(b) +- sqrt(color(blue)(b)^2 - (4color(red)(a)color(green)(c))))/(2 * color(red)(a))#

Substituting:

#color(red)(4)# for #color(red)(a)#

#color(blue)(-3)# for #color(blue)(b)#

#color(green)(7)# for #color(green)(c)# gives:

#p = (-color(blue)(-3) +- sqrt(color(blue)(-3)^2 - (4 * color(red)(4) * color(green)(7))))/(2 * color(red)(4))#

#p = (3 +- sqrt(9 - 112))/8#

#p = (3 +- sqrt(-103))/8#