Question

How do you solve `3( x - 2) ^ { 2} + 5= 26`?

Answer 1

Isolate `x` by doing the opposite of BEDMAS to the total.

Explanation:

Solving implies determining the value of the variable.

In order to solve this equation, we do the opposite of BEDMAS and isolate `x`.

`3(x-2)^2+5=26`

First off, let's "remove" the `5`, by subtracting it from the total.

`3(x-2)^2=21`

Now, we divide everything by `3` to remove the `3`.

`(x-2)^2=7`

Now, we have square root the `7` to remove the squared step.

`x-2=sqrt7`

Finally. we add `2` to the total in order to fully isolate `x`.

`x=sqrt7+2`

We can double check this by subbing in `x=sqrt7+2` and compare the answers.

`3(x-2)^2+5=26`

`3[(sqrt7+2)-2]^2+5=26`

`3[(sqrt7)]^2+5=26`

`3(7)+5=26`

`21+5=26`

`26=26`

Hope this helps :)