First, multiply each side of the equation by #color(red)(6)# (the least common denominator for the two fractions) to eliminate the fractions while keeping the equation balanced:
#color(red)(6)(1/3 + 1/2n) = color(red)(6) xx 4#
#(color(red)(6) xx 1/3) + (color(red)(6) xx 1/2n) = 24#
#color(red)(6)/3 + color(red)(6)/2n = 24#
#2 + 3n = 24#
Next. subtract #color(red)(2)# from each side of the equation to isolate the #n# term while keeping the equation balanced:
#2 - color(red)(2) + 3n = 24 - color(red)(2)#
#0 + 3n = 22#
#3n = 22#
Now, divide each side of the equation by #color(red)(3)# to solve for #n# while keeping the equation balanced:
#(3n)/color(red)(3) = 22/color(red)(3)#
#(color(red)(cancel(color(black)(3)))n)/cancel(color(red)(3)) = 22/3#
#n = 22/3#