Question #dac67

1 Answer
Nov 14, 2017

# => (x+5) (x+1)#

Explanation:

#x^2 + 6x + 5 #

find two numbers such that their sum is equal to the coefficient of middle term (6), and their product is equal to product of coefficients of first and last term (1 x 5 = 5).
Two such numbers are 1 and 5. So we can write the given expression as:

#=> x^2 +5x +1x +5#

# => x(x+5) +1(x+5)#

Now# (x+5)# is common in both the terms, so:

# => (x+5) (x+1)#