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Question #5454a

1 Answer

Nov 14, 2017

$intsin6xdx=-1/6cos6x+C$

Explanation:

$intsin6xdx$

Let $u=6x$
$(du)/dx=6$
$dx=(du)/6$

$intsin6xdx=intsinu(du)/6=1/6intsinudu=1/6(-cosu+C)=-1/6cos6x+C$

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