Question

Question #5454a

Answer 1

`intsin6xdx=-1/6cos6x+C`

Explanation:

`intsin6xdx`

Let `u=6x`
`(du)/dx=6`
`dx=(du)/6`

`intsin6xdx=intsinu(du)/6=1/6intsinudu=1/6(-cosu+C)=-1/6cos6x+C`