Question

How do you solve `-480 >= -8(7a-2) -6a`?

Answer 1

`a>=8`

Explanation:

First Step: (open "()")
`-480>=-56a+16-6a`
`<=> -496>=-62a`

Second Step: switch the places
`-496>=-62a`
`<=> 62a>=496`

Third Step: divided by 62
`62a>=496`
`<=> a>=8`