Question #90833

1 Answer
Nov 15, 2017

See below

Explanation:

Equation A: #x + y + z = 6#
Equation B: #x + y = z#
Equation C: #x - z = 1#

Rearrange equation C to isolate #x#
#x = 1 + z#

Substitute this into equation B
#z+1 + y = z#

Rearrange above equation to isolate #y#
#y = - 1 + z - z#
Therefore #y = -1#

Substitute #x=1+z# and #y=-1# into equation A
#1 + z - 1 + z=6#
#2z = 6#
#z= 3#

And therefore substituting #z=3# into equation C to find #x#
#x - 3 = 1#
#x = 4#