How do you solve #-6( - 10x - 13) = 678#?

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Answer 1 · 2017-11-15T04:05:51

#x=10#

Begin by distributing #-6# to #(-10x-13)#

So, #-6(-10x-13)=[-6*-10x][-6*-13]=60x+78#

Now we have the expression:

#60x+78=678#

We can solve this equation for #x# by subtracting 78 from both sides:

#60xcancel(+78-color(red)78)=678color(red)(-78)#

#60x=600#

Then we divide by #60# to solve for #x#

#cancel60/cancelcolor(red)60x=600/color(red)60#

#x=10#