How many moles of helium is present in 10g of helium?

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Answer 1 · 2017-11-16T14:56:42

#"2.5 mol"#

Mass of one mole of Helium is 4.0 gram

Moles of 10 g of Helium is #= 10 cancel"g" × "1 mol"/(4.0 cancel"g") = "2.5 mol"#

Answer 2 · 2017-11-16T14:57:25

#2.5mols# of helium is present in #10g# of helium.

Firstly, note that the formula for finding moles is;

#"no of moles" = ("mass")/("molar mass")#

Where,
#"mass" = 10g#

#"molar mass" = 4gmol^-1#

Input the values into the formula and solve.

#"no of moles" = 10/4#

#"no of moles" = 2.5mols#

It then means that

#2.5mols# of helium is present in #10g# of helium.