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Answer 1 · 2017-11-17T15:20:20

The answer is #=zlnx#

We have

#z=x^y#

Taking logarithms on both sides

#lnz=ylnx#

#z=e^(ylnx)#

Taking the derivatives wrt #y#

#(delz)/(dely)=lnxe^(ylnx)=lnxe^lnz=zlnx#