Question

Question #f1b9e

Answer 1

Assuming there is an x in front of 29... `(x+4)(7x+1)`

Explanation:

The first step I did was multiply the first term, 7, with the last term 4, which gives us 28.

The next step is to find 2 numbers which, when multiplied, gives you 28, and, when added, gives you 29. 29 is the middle term. Because those 2 numbers are 1 apart, it gives us the hint that the 2 numbers we are trying to find are 1 and 28.

`28*1=28`
`28+1=29`

The next step is to go back to the original problem and split the middle term.

`7x^2+x+28x+4`

Now, we can group the trinomial by factoring x out of the first 2 terms and a 4 out of the second 2 terms.

`7x^2+x+28x+4`
`x(7x+1)+4(7x+1)`
`(x+4)(7x+1)`

And that is the answer.