How do you find the limit of #xlnx# as #x->oo#?

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Answer 1 · 2017-11-18T07:16:39

The answer is #=oo#

In this exercise #x>0#

#lim_(x->oo)x=oo#

#lim_(x->oo)lnx=oo#

Therefore,

#lim_(x->oo)xlnx=oo*oo=oo#

A big number times a big number is a big number.

graph{xlnx [-10, 10, -5, 5]}