Question

How do you solve `4- 1= 5( x + 2)`?

Answer 1

Open brackets on RHS and solve on LHS
`3=5x+10`
Subtract both sides by 10
`3-10=5x cancel(+10) cancel(-10)`
Solve
`-7=5x`
Transfer 5
`-7/5=x`

Answer 2

`x=-7/5`

Explanation:

`4-1=3`

Use the distributive property (`a(b+c)=a*b+a*c`):

`5*x+5*2=3`

`5x+10=3`

`5x=3-10`

`5x=-7`

`x=-7/5`

Answer 3

`x=-7/5`

Explanation:

`4-1=5(x+2)`

`rArr5(x+2)=3`

`"divide both sides by 5"`

`(cancel(5)(x+2))/cancel(5)=3/5`

`rArrx+2=3/5`

`"subtract 2 from both sides"`

`xcancel(+2)cancel(-2)=3/5-2=3/5-10/5=-7/5`

`rArrx=-7/5`

`color(blue)"As a check"`

Substitute this value into the equation and if both sides are equal then it is the solution.

`5(-7/5+2)=5xx3/5=3="left side"`

`rArrx=-7/5" is the solution"`