Question

Question #19db9

Answer 1

`(2+3i)^2=-5+12i`

Explanation:

Laws:
`(a+b)^2=a^2+2*a*b+b^2`
`(a*b)^2=a^2*b^2`
`i=sqrt(-1) => i^2=(sqrt(-1))^2=-1`

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`(2+3i)^2=`
`=2^2+2*2*3i+(3i)^2=`
`=4+12i+(3^2*i^2)=`
`=4+12i+(9*(-1))=`
`=4+12i+(-9)=`
`=-5+12i`