How do you simplify \frac { 6x ^ { 3} - x ^ { 2} - x } { 2x ^ { 2} + x - 1} = \frac { x ^ { 2} - 1} { x ^ { 3} - 2x ^ { 2} + x }?

1 Answer
Nov 19, 2017

3x^3-2x-1

x!=1/2
x!=-1
x!=0
x!=1

Explanation:

(x(3x+1)(2x-1))/((2x-1)(x+1))=((x-1)(x+1))/(x(x-1)^2)
=>
(x(3x+1))/(x+1)=(x+1)/x
=>
x^2(3x+1)=(x+1)^2
=>
3x^3+x^2=x^2+2x+1
=>
3x^3-2x-1