Question

How do you simplify `\frac { 6x ^ { 3} - x ^ { 2} - x } { 2x ^ { 2} + x - 1} = \frac { x ^ { 2} - 1} { x ^ { 3} - 2x ^ { 2} + x }`?

Answer 1

`3x^3-2x-1`

`x!=1/2`
`x!=-1`
`x!=0`
`x!=1`

Explanation:

`(x(3x+1)(2x-1))/((2x-1)(x+1))=((x-1)(x+1))/(x(x-1)^2)`
`=>`
`(x(3x+1))/(x+1)=(x+1)/x`
`=>`
`x^2(3x+1)=(x+1)^2`
`=>`
`3x^3+x^2=x^2+2x+1`
`=>`
`3x^3-2x-1`