How do you evaluate 1/2 +3/(x-2) = (2x+3)/(2x-4)12+3x2=2x+32x4?

1 Answer
Nov 20, 2017

x=1x=1

Explanation:

1/2+3/(x-2)=(2x+3)/(2x-4)12+3x2=2x+32x4

[1*(x-2)+3*2]/[2*(x-2)]=(2x+3)/(2x-4)1(x2)+322(x2)=2x+32x4

(x+4)/(2x-4)=(2x+3)/(2x-4)x+42x4=2x+32x4

x+4=2x+3x+4=2x+3

x=1x=1